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Blumentals Rapid PHP 2020 16.0.0.225 Crack [Full Review]

EASEUS Data Recovery Wizard 12.9.1 .Q:

In how many ways can $12$ balls be chosen from $5$ colored and numbered balls?

In how many ways can $12$ balls be chosen from $5$ colored and numbered balls?

There are two colored balls that I can choose from them:

color of $1$ can be chosen in $5$ ways
color of $2$ can be chosen in $4$ ways

Then the number of such balls can be calculated as
$$
\begin{align}
\binom{5}{1}\binom{4}{1}
\end{align}
$$
Then the total number of ways can be calculated as
$$
\begin{align}
\binom{5}{1}\binom{4}{1}\binom{3}{1}\binom{2}{1}
\end{align}
$$
Is this correct? If not, please correct me.

A:

Yes, your reasoning is correct.
Other more conceptual approaches are also viable.
If you view the question as choosing two from $\{5,4,3,2,1\}$ then you have only one way to choose them, and this happens $\binom52=5\cdot 4$ times.
However, if you view the question as choosing three (but not necessarily distinct) ordered pairs, then you have $\binom52=\frac{5!}{3!2!}$ ways.

Q:

Is there a way to convert a string to a hex string in Python?

Is there any way to convert a string to a hex string like d0de4d4a to d4a in python.
Suppose this is my string:
str = ‘\xd4\xc1\xd8\x00\x30’

I used
str.encode(‘hex’)

But as I mentioned it just returns d4a as a result.
Is there any way to get the result I want?

A:

You can use hex() builtin:
>>> str.hex()
‘0x4c1’
>>> hex(0x4c1)
‘0x4c1’
>>> 0x4c1
0x4c1
>>> hex

0644bf28c6

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